What is 2y+13+x^2=8x-y^2 ?

The solution to 2y+13+x^2=8x-y^2 is Circle with (a,b)=(4,-1),r=2

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2y+13+x^2=8x-y^2

2 y + 13 + x^{2} = 8 x - y^{2}

(a, b) = (4, - 1), r = 2

Solution steps

2 y + 13 + x^{2} = 8 x - y^{2}

Rewrite

2 y + 13 + x^{2} = 8 x - y^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 1))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (4, - 1), r = 2

2 x^{2} + 2 y^{2} + 8 x - 6 y + 4 = 0

(x - 5)^{2} + (y + 2)^{2} = 9

x^{2} + y^{2} = 85

(x - 1)^{2} + (y - 2)^{2} = 81

a^{2} + b^{2} = 64

What is 2y+13+x^2=8x-y^2 ?
The solution to 2y+13+x^2=8x-y^2 is Circle with (a,b)=(4,-1),r=2