What is (x-9)^2+(y+4)^2=25 ?

The solution to (x-9)^2+(y+4)^2=25 is Circle with (a,b)=(9,-4),r=5

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(x-9)^2+(y+4)^2=25

(x - 9)^{2} + (y + 4)^{2} = 25

(a, b) = (9, - 4), r = 5

Solution steps

(x - 9)^{2} + (y + 4)^{2} = 25

Rewrite

(x - 9)^{2} + (y + 4)^{2} = 25

in the form of the standard circle equation

(x - 9)^{2} + (y - (- 4))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (9, - 4), r = 5

2 x^{2} + 2 y^{2} + 10 x - 6 y - 55 = 0

x^{2} + y^{2} - 8 y + 7 = 0

(x - 4)^{2} + (y - 2)^{2} = 9

x^{2} + y^{2} - 10 x + 6 y - 66 = 0

x^{2} + y^{2} + 2 x + y + 1 = 0

What is (x-9)^2+(y+4)^2=25 ?
The solution to (x-9)^2+(y+4)^2=25 is Circle with (a,b)=(9,-4),r=5