What is x^2+y^2+14x-10y+65=0 ?

The solution to x^2+y^2+14x-10y+65=0 is Circle with (a,b)=(-7,5),r=3

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x^2+y^2+14x-10y+65=0

x^{2} + y^{2} + 14 x - 10 y + 65 = 0

(a, b) = (- 7, 5), r = 3

Solution steps

x^{2} + y^{2} + 14 x - 10 y + 65 = 0

Rewrite

x^{2} + y^{2} + 14 x - 10 y + 65 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 5)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 7, 5), r = 3

x^{2} + y^{2} - 6 x + 8 y + 24 = 0

(x + 1)^{2} + (y + 6)^{2} = 19

(x + 5)^{2} + (y - 2)^{2} = 16

x^{2} + y^{2} + 10 y - 75 = 0

9 = 2 y - y^{2} - 6 x - x^{2}

What is x^2+y^2+14x-10y+65=0 ?
The solution to x^2+y^2+14x-10y+65=0 is Circle with (a,b)=(-7,5),r=3