What is the perpendicular y= 2/5 x+1,(10,-8) ?

The perpendicular y= 2/5 x+1,(10,-8) is y=-5/2 x+17

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perpendicular y= 2/5 x+1,(10,-8)

perpendicular

y = - \frac{5}{2} x + 17

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{2}{5} x + 1

that passes through

(10, - 8)

Find the slope of

y = \frac{2}{5} x + 1 : m = \frac{2}{5}

Compute the slope of the perpendicular line:

m_{p} = - \frac{5}{2}

Find the line with slope m=

- \frac{5}{2}

and passing through

(10, - 8) : y = - \frac{5}{2} x + 17

y = - \frac{5}{2} x + 17

What is the perpendicular y= 2/5 x+1,(10,-8) ?
The perpendicular y= 2/5 x+1,(10,-8) is y=-5/2 x+17