What is the domain of f(x)= 1/(x^2-x+1) ?

The domain of f(x)= 1/(x^2-x+1) is -infinity <x<infinity

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domain of f(x)= 1/(x^2-x+1)

domain

f (x) = \frac{1}{x ^{2} - x + 1}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = 3^{x - 2}

3 x + y = - 2

f (x) = e^{x^{2}} + ln (x^{2})

6 x + 1

y = x + 8

What is the domain of f(x)= 1/(x^2-x+1) ?
The domain of f(x)= 1/(x^2-x+1) is -infinity <x<infinity