求反函数 e^{1/(s(s+1))}

解答

求反函数

e^{\cdot \frac{1}{s \cdot ( s + 1 )}}

\frac{- ln ( s ) + ln ^{2} ( s ) + 4 ln ( s )}{2 ln ( s )}, \frac{- ln ( s ) - ln ^{2} ( s ) + 4 ln ( s )}{2 ln ( s )}

求解步骤

y = e^{\frac{1}{s ( s + 1 )}}

用

y

替代

s

s = e^{\frac{1}{y ( y + 1 )}}

求解

y, s = e^{\cdot \frac{1}{y \cdot ( y + 1 )}}

\frac{- ln ( s ) + ln ^{2} ( s ) + 4 ln ( s )}{2 ln ( s )}, \frac{- ln ( s ) - ln ^{2} ( s ) + 4 ln ( s )}{2 ln ( s )}

a sy m pt o t es f (x) = \frac{x - 5}{x ^{2} - 8 x + 15}

in t erce pt s \frac{- 4 x - 12}{x ^{2} - 9}

in t erce pt s x^{4} + 2 x^{3} - 2 x^{2} - 3 x + 2

e x t re m e f (x) = - x^{2} + 5 x - 2

d o main 4 x^{2} - 6 x