What is the domain of f(x)=ln((x+1)/(x+2)) ?

The domain of f(x)=ln((x+1)/(x+2)) is x -1

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domain of f(x)=ln((x+1)/(x+2))

domain

f (x) = ln (\frac{x + 1}{x + 2})

x < - 2 or x > - 1

Interval Notation

(- \infty, - 2) \cup (- 1, \infty)

Solution steps

Find positive values for logs:

x < - 2 or x > - 1

Find undefined (singularity) points:

x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or x > - 1

f (x) = \frac{x ^{2} - 9}{x ^{2} - 4}

f (x) = \frac{x + 1}{x - 4}

f (x) = \frac{x ^{3}}{x ^{2} - 1}

\frac{1}{x ^{2} + 1}

What is the domain of f(x)=ln((x+1)/(x+2)) ?
The domain of f(x)=ln((x+1)/(x+2)) is x<-2\lor x>-1