What is the domain of f(x)= 1/(sqrt(x-2)) ?

The domain of f(x)= 1/(sqrt(x-2)) is x>2

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domain of f(x)= 1/(sqrt(x-2))

domain

f (x) = \frac{1}{x - 2}

x > 2

Solution steps

Find non-negative values for radicals:

x \geq 2

Find undefined (singularity) points:

x = 2

Combine real regions and undefined points for final function domain

x > 2

f (x) = (x - 6)^{3}

f (x) = \frac{( 2 x ^{2} - 2 )}{x ^{2} - 9}

(4, - 3), (- 5, 2)

f (x) = 20.4

f (x) = x^{3} + 12 x^{2} - 27 x + 11

What is the domain of f(x)= 1/(sqrt(x-2)) ?
The domain of f(x)= 1/(sqrt(x-2)) is x>2