monotone f(x)=(x-6)^3

解答

单调区间

f (x) = (x - 6)^{3}

递增 : - \infty < x < 6, 递增 : 6 < x < \infty

求解步骤

f^{'} (x) = 3 (x - 6)^{2}

Find intervals:

递增

: - \infty < x < 6,

递增

: 6 < x < \infty

递增 : - \infty < x < 6, 递增 : 6 < x < \infty

a sy m pt o t es f (x) = \frac{( 2 x ^{2} - 2 )}{x ^{2} - 9}

l in e (4, - 3), (- 5, 2)

r an g e f (x) = 20.4

e x t re m e f (x) = x^{3} + 12 x^{2} - 27 x + 11

in v erse \frac{x}{x}