What is the inverse of y=(3x-4)^2 ?

The inverse of y=(3x-4)^2 is (sqrt(x)+4)/3 ,(-sqrt(x)+4)/3

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inverse of y=(3x-4)^2

inverse

y = (3 x - 4)^{2}

\frac{x + 4}{3}, \frac{- x + 4}{3}

Solution steps

y = (3 x - 4)^{2}

Replace

x

with

y

x = (3 y - 4)^{2}

Solve for

y, x = (3 y - 4)^{2}

\frac{x + 4}{3}, \frac{- x + 4}{3}

y = - \frac{2}{3} x (6.1)

f (x) = 2 x^{2}

f (x) = 3 x^{4}

x + 9 y = 6

y + 8 = - 2 (x + 6)

What is the inverse of y=(3x-4)^2 ?
The inverse of y=(3x-4)^2 is (sqrt(x)+4)/3 ,(-sqrt(x)+4)/3