What is the inverse of-(10)/(x^2) ?

The inverse of-(10)/(x^2) is sqrt(-(10)/x),-sqrt(-(10)/x)

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inverse of-(10)/(x^2)

inverse

- \frac{10}{x ^{2}}

- \frac{10}{x}, - - \frac{10}{x}

Solution steps

y = - \frac{10}{x ^{2}}

Replace

x

with

y

x = - \frac{10}{y ^{2}}

Solve for

y, x = - \frac{10}{y ^{2}}

- \frac{10}{x}, - - \frac{10}{x}

f (x) = (x + 4)^{\frac{2}{7}}

y = x^{2} + x

f (x) = \frac{\frac{3}{2}}{2 \frac{5}{2} + \frac{3}{2} x}

x - 5

f (x) = - \frac{x ^{2}}{2} - 3 x - \frac{1}{2}

What is the inverse of-(10)/(x^2) ?
The inverse of-(10)/(x^2) is sqrt(-(10)/x),-sqrt(-(10)/x)