What is the inverse of sqrt(-4x^2+12) ?

The inverse of sqrt(-4x^2+12) is sqrt(-(x^2-12)/4),-sqrt(-(x^2-12)/4)

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inverse of sqrt(-4x^2+12)

inverse

- 4 x^{2} + 12

- \frac{x ^{2} - 12}{4}, - - \frac{x ^{2} - 12}{4}

Solution steps

y = - 4 x^{2} + 12

Replace

x

with

y

x = - 4 y^{2} + 12

Solve for

y, x = - 4 y^{2} + 12

- \frac{x ^{2} - 12}{4}, - - \frac{x ^{2} - 12}{4}

tan (x + \frac{π}{4})

f (x) = \frac{x + 9}{x ^{2} - 81}

(- 8, 8), (1, - 10)

f (x) = \frac{4 + x}{8 - x}

x^{2} + 2 x - 3

What is the inverse of sqrt(-4x^2+12) ?
The inverse of sqrt(-4x^2+12) is sqrt(-(x^2-12)/4),-sqrt(-(x^2-12)/4)