What is the critical 4x^3+7x^2-20x ?

The critical 4x^3+7x^2-20x is x=-2,x= 5/6

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critical 4x^3+7x^2-20x

critical points

4 x^{3} + 7 x^{2} - 20 x

x = - 2, x = \frac{5}{6}

Solution steps

4 x^{3} + 7 x^{2} - 20 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = \frac{5}{6}

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} + 7 x^{2} - 20 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = \frac{5}{6}

f (x) = x^{2} + 2 x - 1

\frac{x + 8}{3}

y = e^{c s c (6 x) t a n (6 x)}

- 2 x^{2} + 2 x - 4

1.4 x^{2} + 2 x + 1