What is the range of (x+8)/3 ?

The range of (x+8)/3 is -infinity <f(x)<infinity

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range of (x+8)/3

range

\frac{x + 8}{3}

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The range of polynomials with odd degree is all the real numbers

- \infty < f (x) < \infty

y = e^{c s c (6 x) t a n (6 x)}

- 2 x^{2} + 2 x - 4

1.4 x^{2} + 2 x + 1

f (x) = (\frac{1}{2}) x - 7

f (x) = \frac{6}{\frac{4}{x} - 1}