What is the domain of f(x)=(2x+1)/(x^2-x-6) ?

The domain of f(x)=(2x+1)/(x^2-x-6) is x 3

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domain of f(x)=(2x+1)/(x^2-x-6)

domain

f (x) = \frac{2 x + 1}{x ^{2} - x - 6}

x < - 2 or - 2 < x < 3 or x > 3

Interval Notation

(- \infty, - 2) \cup (- 2, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 2

The function domain

x < - 2 or - 2 < x < 3 or x > 3

f (x) = (x^{2} - 1)^{3}

1

x^{5} - 5 x

\frac{( x + 3 ) ( x - 3 )}{x ^{2} + 9}

cos (\frac{x}{4} + \frac{π}{4}) - 2

What is the domain of f(x)=(2x+1)/(x^2-x-6) ?
The domain of f(x)=(2x+1)/(x^2-x-6) is x<-2\lor-2<x<3\lor x>3