What is the extreme sqrt(3)tan^2(x) ?

The extreme sqrt(3)tan^2(x) is Minimum(pin,0)

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extreme sqrt(3)tan^2(x)

extreme points

3 tan^{2} (x)

Minimum (πn, 0)

Solution steps

Find the critical points:

x = πn

Domain of

3 tan^{2} (x) : πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

Find intervals:

Increasing

: πn < x < \frac{π}{2} + πn,

Decreasing

: \frac{π}{2} + πn < x < π + πn

Plug the extreme point

x = πn

into

3 tan^{2} (x) \Rightarrow y = 0

Minimum (πn, 0)

f (x) = \frac{3}{2} x + 12

x^{5} - 5 x^{3}

y = - \frac{1}{2} (x - 1) + 4

8 x^{4} - 8 x^{2} + 1

y = - 2 (5)^{x - 4} + 3

What is the extreme sqrt(3)tan^2(x) ?
The extreme sqrt(3)tan^2(x) is Minimum(pin,0)