What is the critical x^5-5x^3 ?

The critical x^5-5x^3 is x=-sqrt(3),x=0,x=sqrt(3)

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critical x^5-5x^3

critical points

x^{5} - 5 x^{3}

x = - 3, x = 0, x = 3

Solution steps

x^{5} - 5 x^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 0, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{5} - 5 x^{3} : - \infty < x < \infty

All critical points are in domain

x = - 3, x = 0, x = 3

y = - \frac{1}{2} (x - 1) + 4

8 x^{4} - 8 x^{2} + 1

y = - 2 (5)^{x - 4} + 3

f (x) = \frac{x ^{2} + 6 x - 8}{x - 4}

f (x) = \frac{x + 3}{x - 7}

What is the critical x^5-5x^3 ?
The critical x^5-5x^3 is x=-sqrt(3),x=0,x=sqrt(3)