What is the domain of (x+9)/(8x^2-x-9) ?

The domain of (x+9)/(8x^2-x-9) is x 9/8

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domain of (x+9)/(8x^2-x-9)

domain

\frac{x + 9}{8 x ^{2} - x - 9}

x < - 1 or - 1 < x < \frac{9}{8} or x > \frac{9}{8}

Interval Notation

(- \infty, - 1) \cup (- 1, \frac{9}{8}) \cup (\frac{9}{8}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{9}{8}, x = - 1

The function domain

x < - 1 or - 1 < x < \frac{9}{8} or x > \frac{9}{8}

f (x) = 3 \cdot sec (2 x + \frac{π}{2}) + 2

\frac{x}{x ^{2} - x - 6}

f (x) = 5 x^{2} - 11 x + 8

f (x) = 3 x - 2

x = y^{2} + 2

What is the domain of (x+9)/(8x^2-x-9) ?
The domain of (x+9)/(8x^2-x-9) is x<-1\lor-1<x< 9/8 \lor x> 9/8