What is the domain of f(x)=sqrt(3x-2) ?

The domain of f(x)=sqrt(3x-2) is x>= 2/3

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domain of f(x)=sqrt(3x-2)

domain

f (x) = 3 x - 2

x \geq \frac{2}{3}

Interval Notation

[\frac{2}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{2}{3}

The function domain

x \geq \frac{2}{3}

x = y^{2} + 2

f (x) = - 64 x^{2} + 4300 x - 5140

f (x) = (x + 5)^{2} + 3

f (x) = \frac{1}{4} x^{2} - 3 x - 7

f (x) = 6 - 3 x

What is the domain of f(x)=sqrt(3x-2) ?
The domain of f(x)=sqrt(3x-2) is x>= 2/3