What is the inverse of f(x)=\sqrt[5]{x}+4 ?

The inverse of f(x)=\sqrt[5]{x}+4 is x^5-20x^4+160x^3-640x^2+1280x-1024

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[5]{x}+4

inverse

x^{5} - 20 x^{4} + 160 x^{3} - 640 x^{2} + 1280 x - 1024

Solution steps

Replace

x

with

y

Solve for

x^{5} - 20 x^{4} + 160 x^{3} - 640 x^{2} + 1280 x - 1024

f (x) = 2 sin (π x + 3) - 3

f (x) = \frac{3 x + 4}{2 - x}

x^{2} - 6 x + 5

\frac{x + 2}{x - 3}

y = cos (5 x)

What is the inverse of f(x)=\sqrt[5]{x}+4 ?
The inverse of f(x)=\sqrt[5]{x}+4 is x^5-20x^4+160x^3-640x^2+1280x-1024