What is the range of (x+2)/(x-3) ?

The range of (x+2)/(x-3) is f(x) 1

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range of (x+2)/(x-3)

range

\frac{x + 2}{x - 3}

f (x) < 1 or f (x) > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{x + 2}{x - 3}

Inverse of

\frac{x + 2}{x - 3} : \frac{2 + 3 x}{x - 1}

\frac{2 + 3 x}{x - 1}

Find the domain of each inverse function

Domain of

\frac{2 + 3 x}{x - 1} : x < 1 or x > 1

Combine the intervals

f (x) < 1 or f (x) > 1

y = cos (5 x)

f (x) = \frac{1}{3} x^{3} - x^{2} - 8 x + 1

x^{2} + 7

- \frac{31}{( 6 + t ) ^{2}}

y = x^{x^{x}}

What is the range of (x+2)/(x-3) ?
The range of (x+2)/(x-3) is f(x)<1\lor f(x)>1