What is the inverse of f(x)= 1/5 x^2 ?

The inverse of f(x)= 1/5 x^2 is sqrt(5)sqrt(x),-sqrt(5)sqrt(x)

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inverse of f(x)= 1/5 x^2

inverse

f (x) = \frac{1}{5} x^{2}

5 x, - 5 x

Solution steps

y = \frac{1}{5} x^{2}

Replace

x

with

y

x = \frac{1}{5} y^{2}

Solve for

y, x = \frac{1}{5} y^{2}

5 x, - 5 x

(2 - x) e^{x}

x + 4 + 5 - x

f (x) = \frac{6}{x - 2}

f (x) = 3^{x + 5} - 1

f (x) = \frac{2 x}{x ^{2} - 9}

What is the inverse of f(x)= 1/5 x^2 ?
The inverse of f(x)= 1/5 x^2 is sqrt(5)sqrt(x),-sqrt(5)sqrt(x)