What is the domain of g(t)=-9/(2t^{3/2)} ?

The domain of g(t)=-9/(2t^{3/2)} is t>0

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domain of g(t)=-9/(2t^{3/2)}

domain

g (t) = - \frac{9}{2 t ^{\frac{3}{2}}}

t > 0

Interval Notation

(0, \infty)

Solution steps

Find non-negative values for radicals:

t \geq 0

Find undefined (singularity) points:

t = 0

Combine real regions and undefined points for final function domain

t > 0

f (x) = \frac{x ^{2} + 1}{x ^{2} - 1}

x^{4} - 12 x^{3}

\frac{6 x}{x - 5}

(- 4, 6), (6, 4)

\frac{2}{x - 1} + 1

What is the domain of g(t)=-9/(2t^{3/2)} ?
The domain of g(t)=-9/(2t^{3/2)} is t>0