What is the perpendicular y= 3/2 x+0,(-4,2) ?

The perpendicular y= 3/2 x+0,(-4,2) is y=-2/3 x-2/3

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perpendicular y= 3/2 x+0,(-4,2)

perpendicular

y = \frac{3}{2} x + 0, (- 4, 2)

y = - \frac{2}{3} x - \frac{2}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = \frac{3}{2} x + 0

that passes through

(- 4, 2)

Find the slope of

y = \frac{3}{2} x + 0 : m = \frac{3}{2}

Compute the slope of the perpendicular line:

m_{p} = - \frac{2}{3}

Find the line with slope m=

- \frac{2}{3}

and passing through

(- 4, 2) : y = - \frac{2}{3} x - \frac{2}{3}

y = - \frac{2}{3} x - \frac{2}{3}

f (x) = \frac{x}{x ^{2} - 2 x - 35}

- (\frac{1}{2})^{x} - 1

f (x) = \frac{2 x + 18}{2 x ^{2} + 13 x - 45}

(5, 6), (7, 8)

f (x) = \frac{2 x ^{2} + 1}{2 x ^{3} - 4 x ^{2}}

What is the perpendicular y= 3/2 x+0,(-4,2) ?
The perpendicular y= 3/2 x+0,(-4,2) is y=-2/3 x-2/3