What is the domain of f(x)=sqrt(x/(x^2-2x-35)) ?

The domain of f(x)=sqrt(x/(x^2-2x-35)) is -5 7

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domain of f(x)=sqrt(x/(x^2-2x-35))

domain

f (x) = \frac{x}{x ^{2} - 2 x - 35}

- 5 < x \leq 0 or x > 7

Interval Notation

(- 5, 0] \cup (7, \infty)

Solution steps

Find non-negative values for radicals:

- 5 < x \leq 0 or x > 7

Find undefined (singularity) points:

x = 7, x = - 5

Combine real regions and undefined points for final function domain

- 5 < x \leq 0 or x > 7

- (\frac{1}{2})^{x} - 1

f (x) = \frac{2 x + 18}{2 x ^{2} + 13 x - 45}

(5, 6), (7, 8)

f (x) = \frac{2 x ^{2} + 1}{2 x ^{3} - 4 x ^{2}}

5 x - y = 3

What is the domain of f(x)=sqrt(x/(x^2-2x-35)) ?
The domain of f(x)=sqrt(x/(x^2-2x-35)) is -5<x<= 0\lor x>7