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Beliebt Funktionen >

extreme f(x)=-0.001x^2+9x-1296

Lösung

extrempunkte

f (x) = - 0.001 x^{2} + 9 x - 1296

Lösung

Maximum (4500, 18954)

Schritte zur Lösung

f^{'} (x) = - 0.002 x + 9

Intervalle finden:

Ansteigend

: - \infty < x < 4500,

Absteigend

: 4500 < x < \infty

Stecke

x = 4500

in

- 0.001 x^{2} + 9 x - 1296 : 18954

Maximum (4500, 18954)

Graph

Beliebte Beispiele

extreme f(x)=((500+500*x))/(1+0.04*x^2)

e x t re m e f (x) = \frac{( 500 + 500 \cdot x )}{1 + 0.04 \cdot x ^{2}}

extreme ((x^2+2))/((x^2-16))

e x t re m e \frac{( x ^{2} + 2 )}{( x ^{2} - 16 )}

extreme y=2x^2+5

e x t re m e y = 2 x^{2} + 5

extreme f(x)=5x^4-20x^3+1

e x t re m e f (x) = 5 x^{4} - 20 x^{3} + 1

extreme f(x)=0.001x^2+3.2x-10

e x t re m e f (x) = 0.001 x^{2} + 3.2 x - 10