What is the perpendicular y=x-3,(-2,1) ?

The perpendicular y=x-3,(-2,1) is y=-x-1

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perpendicular y=x-3,(-2,1)

perpendicular

y = x - 3, (- 2, 1)

y = - x - 1

Solution steps

Find the line

y = mx + b

perpendicular to

y = x - 3

that passes through

(- 2, 1)

Find the slope of

y = x - 3 : m = 1

Compute the slope of the perpendicular line:

m_{p} = - 1

Find the line with slope m=

- 1

and passing through

(- 2, 1) : y = - x - 1

y = - x - 1

f (x) = \frac{x ^{2}}{x ^{2} + 1}

f (x) = x^{2} + 5 x - 14

f (x) = \frac{1}{( x - 3 )}

y + 6 = \frac{1}{3} (x - 4)

f (x) = 3 x^{3}

What is the perpendicular y=x-3,(-2,1) ?
The perpendicular y=x-3,(-2,1) is y=-x-1