extreme x^3-2x^2-4x+4

Lösung

extrempunkte

x^{3} - 2 x^{2} - 4 x + 4

Maximum (- \frac{2}{3}, \frac{148}{27}), Minimum (2, - 4)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 4 x - 4

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{2}{3},

Absteigend

: - \frac{2}{3} < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = - \frac{2}{3}

x^{3} - 2 x^{2} - 4 x + 4 : \frac{148}{27}

Maximum (- \frac{2}{3}, \frac{148}{27})

Stecke

x = 2

x^{3} - 2 x^{2} - 4 x + 4 : - 4

Minimum (2, - 4)

Maximum (- \frac{2}{3}, \frac{148}{27}), Minimum (2, - 4)

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