What is the critical x^3-3x^2-4 ?

The critical x^3-3x^2-4 is x=0,x=2

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critical x^3-3x^2-4

critical points

x^{3} - 3 x^{2} - 4

x = 0, x = 2

Solution steps

x^{3} - 3 x^{2} - 4

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 3 x^{2} - 4 : - \infty < x < \infty

All critical points are in domain

x = 0, x = 2

x^{2} (x - 1)^{3}

f (x) = 2 - 3 x

f (x) = \frac{1}{2} x^{2} - 1

f (x) = \frac{5 x ^{3} + 4 x - 2}{4 x}

f (x) = \frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2}