What is the critical x^2(x-1)^3 ?

The critical x^2(x-1)^3 is x=0,x= 2/5 ,x=1

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critical x^2(x-1)^3

critical points

x^{2} (x - 1)^{3}

x = 0, x = \frac{2}{5}, x = 1

Solution steps

x^{2} (x - 1)^{3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = \frac{2}{5}, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{2} (x - 1)^{3} : - \infty < x < \infty

All critical points are in domain

x = 0, x = \frac{2}{5}, x = 1

f (x) = 2 - 3 x

f (x) = \frac{1}{2} x^{2} - 1

f (x) = \frac{5 x ^{3} + 4 x - 2}{4 x}

f (x) = \frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2}

f (x) = 6 x - x^{2}