What is the derivative of x^2y-x ?

The derivative of x^2y-x is 2xy+(dy)/(dx)x^2-1

What is the first derivative of x^2y-x ?

The first derivative of x^2y-x is 2xy+(dy)/(dx)x^2-1

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\frac{d}{d x} (x^{2} y - x)

2 x y + \frac{d y}{d x} x^{2} - 1

Solution steps

\frac{d}{d x} (x^{2} y - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} y) - \frac{d x}{d x}

\frac{d}{d x} (x^{2} y) = 2 x y + \frac{d y}{d x} x^{2}

\frac{d x}{d x} = 1

= 2 x y + \frac{d y}{d x} x^{2} - 1

\int (cos (5 x) cos (3 x)) d x

\int_{0}^{1} x - x^{3} d x

\frac{\partial}{\partial x} (e^{- x^{3} - y^{3}})

5^{t}

f (x) = sin (x^{5})

What is the derivative of x^2y-x ?
The derivative of x^2y-x is 2xy+(dy)/(dx)x^2-1
What is the first derivative of x^2y-x ?
The first derivative of x^2y-x is 2xy+(dy)/(dx)x^2-1