What is the integral of (cos(5x)cos(3x)) ?

The integral of (cos(5x)cos(3x)) is 1/2 (1/8 sin(8x)+1/2 sin(2x))+C

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integral of (cos(5x)cos(3x))

\int (cos (5 x) cos (3 x)) d x

\frac{1}{2} (\frac{1}{8} sin (8 x) + \frac{1}{2} sin (2 x)) + C

Solution steps

\int cos (5 x) cos (3 x) d x

Rewrite using trig identities

= \int \frac{1}{2} (cos (8 x) + cos (2 x)) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int cos (8 x) + cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int cos (8 x) d x + \int cos (2 x) d x)

\int cos (8 x) d x = \frac{1}{8} sin (8 x)

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

= \frac{1}{2} (\frac{1}{8} sin (8 x) + \frac{1}{2} sin (2 x))

Add a constant to the solution

= \frac{1}{2} (\frac{1}{8} sin (8 x) + \frac{1}{2} sin (2 x)) + C

\int_{0}^{1} x - x^{3} d x

\frac{\partial}{\partial x} (e^{- x^{3} - y^{3}})

5^{t}

f (x) = sin (x^{5})

\frac{d}{d x} (\frac{- 5}{x ^{2}})

What is the integral of (cos(5x)cos(3x)) ?
The integral of (cos(5x)cos(3x)) is 1/2 (1/8 sin(8x)+1/2 sin(2x))+C