(\partial)/(\partial y)(sqrt(16-x^2-4y))

Lösung

\frac{\partial}{\partial y} (16 - x^{2} - 4 y)

- \frac{2}{16 - x ^{2} - 4 y}

Schritte zur Lösung

\frac{\partial}{\partial y} (16 - x^{2} - 4 y)

Behandle

x

als Konstante

Wende die Kettenregel an:

\frac{1}{2 16 - x ^{2} - 4 y} \frac{\partial}{\partial y} (16 - x^{2} - 4 y)

= \frac{1}{2 16 - x ^{2} - 4 y} \frac{\partial}{\partial y} (16 - x^{2} - 4 y)

\frac{\partial}{\partial y} (16 - x^{2} - 4 y) = - 4

= \frac{1}{2 16 - x ^{2} - 4 y} (- 4)

Vereinfache

\frac{1}{2 16 - x ^{2} - 4 y} (- 4) : - \frac{2}{16 - x ^{2} - 4 y}

= - \frac{2}{16 - x ^{2} - 4 y}

y^{^{''}} - y = sin (2 t)

d er i v a t i v e f (x) = \frac{e ^{x}}{x + 3}

in v erse l a pl a ce \frac{( s + 5 )}{( s ^{2} + 4 s + 13 )}

\frac{d}{d x} (x^{2} (1 - x)^{3})

\int \frac{( tan ^{3} ( ln ( x ) ) )}{6 x} d x