What is the solution for (dy)/(dt)=y(1-y),y(0)=16 ?

The solution for (dy)/(dt)=y(1-y),y(0)=16 is y=(16e^t)/(-15+16e^t)

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(dy)/(dt)=y(1-y),y(0)=16

\frac{d y}{d t} = y (1 - y), y (0) = 16

y = \frac{16 e ^{t}}{- 15 + 16 e ^{t}}

Solution steps

\frac{d y}{d t} = y (1 - y)

Solve Bernoulli ODE:

y = \frac{16 e ^{t}}{- 15 + 16 e ^{t}}

y = \frac{16 e ^{t}}{- 15 + 16 e ^{t}}

\int \frac{t ^{2} - 1}{t ^{4} - 1} d t

y^{^{''}} + 4 y^{^{'}} + 4 y = e^{- 2 x} \cdot ln (x)

\frac{d}{d x} (\frac{sin ( x )}{b sin ( b x )})

y^{^{'}} - 2 x y = 2 x e^{x^{2}}

((4 x^{2} + 5)^{2} \cdot (7 x)^{2 x})^{^{'}}

What is the solution for (dy)/(dt)=y(1-y),y(0)=16 ?
The solution for (dy)/(dt)=y(1-y),y(0)=16 is y=(16e^t)/(-15+16e^t)