What is the solution for y^'-2xy=2xe^{x^2} ?

The solution for y^'-2xy=2xe^{x^2} is y=e^{x^2}x^2+c_{1}e^{x^2}

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y^'-2xy=2xe^{x^2}

y^{^{'}} - 2 x y = 2 x e^{x^{2}}

y = e^{x^{2}} x^{2} + c_{1} e^{x^{2}}

Solution steps

y^{'} (x) - 2 x y = 2 x e^{x^{2}}

Solve linear ODE:

y = e^{x^{2}} x^{2} + c_{1} e^{x^{2}}

y = e^{x^{2}} x^{2} + c_{1} e^{x^{2}}

((4 x^{2} + 5)^{2} \cdot (7 x)^{2 x})^{^{'}}

- 4 x^{2} y + y^{^{'}} = 4 x^{2}

\int \frac{1}{12 x + 12 x} d x

\int x \cdot (7 - x)^{9} d x

\frac{d}{d x} (\frac{1}{4 ( 1 + x ) ^{\frac{3}{4}}})

What is the solution for y^'-2xy=2xe^{x^2} ?
The solution for y^'-2xy=2xe^{x^2} is y=e^{x^2}x^2+c_{1}e^{x^2}