What is the derivative of y=3x+4/x ?

The derivative of y=3x+4/x is 3-4/(x^2)

What is the first derivative of y=3x+4/x ?

The first derivative of y=3x+4/x is 3-4/(x^2)

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derivative of

y = 3 x + \frac{4}{x}

3 - \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (3 x + \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 3 - \frac{4}{x ^{2}}

\frac{d u + 2 d v}{u + 2 v} = 0

x \to 2 lim (3 x^{2} - 2 x + 1)

f (x) = \frac{7 x ^{2} + 7 x + 7}{x}

y = (x^{(3)} - 4 x)^{(12)} (2)

\frac{\partial}{\partial y} (y + cos^{2} (x))

What is the derivative of y=3x+4/x ?
The derivative of y=3x+4/x is 3-4/(x^2)
What is the first derivative of y=3x+4/x ?
The first derivative of y=3x+4/x is 3-4/(x^2)