integral from 0 to 3 of |x-1|

Lösung

\int_{0}^{3} ∣ x - 1 ∣ d x

\frac{5}{2}

Dezimale

2.5

Schritte zur Lösung

\int_{0}^{3} ∣ x - 1 ∣ d x

Entferne die Extremwerte

= \int_{0}^{1} - x + 1 d x + \int_{1}^{3} x - 1 d x

\int_{0}^{1} - x + 1 d x = \frac{1}{2}

\int_{1}^{3} x - 1 d x = 2

= \frac{1}{2} + 2

Vereinfache

\frac{1}{2} + 2 : \frac{5}{2}

= \frac{5}{2}

\int_{0}^{1} 1 + x^{2} d x

\int_{0}^{5} π (2 x)^{2} d x

\int \frac{( sec ^{2} ( x ) )}{tan ^{2} ( x )} d x

\frac{d}{d x} y = (\frac{1}{cos ^{2} ( x )})

x \to - 9 lim (\frac{8 x + 72}{∣ x + 9 ∣})