xy^2y^'=y^3-4x^3,y(1)=4

Lösung

x y^{2} y^{^{'}} = y^{3} - 4 x^{3}, y (1) = 4

y = 34 x 3 - 3 ln (x) + 16

Schritte zur Lösung

x y^{2} y^{'} (x) = y^{3} - 4 x^{3}

Solve Bernoulli ODE:

y = 34 x 3 - 3 ln (x) + 16

y = 34 x 3 - 3 ln (x) + 16

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