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Beliebt Rechnen >

f^'(x)= 1/((1-x^2)^2)

Lösung

f^{^{'}} (x) = \frac{1}{( 1 - x ^{2} ) ^{2}}

Lösung

f (x) = \frac{1}{4} ln (x + 1) - \frac{1}{4 ( x + 1 )} - \frac{1}{4} ln (x - 1) - \frac{1}{4 ( x - 1 )} + c_{1}

Schritte zur Lösung

f^{'} (x) = \frac{1}{( 1 - x ^{2} ) ^{2}}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int \frac{1}{( 1 - x ^{2} ) ^{2}} d x

\int \frac{1}{( 1 - x ^{2} ) ^{2}} d x = \frac{1}{4} ln (x + 1) - \frac{1}{4 ( x + 1 )} - \frac{1}{4} ln (x - 1) - \frac{1}{4 ( x - 1 )} + c_{1}

f (x) = \frac{1}{4} ln (x + 1) - \frac{1}{4 ( x + 1 )} - \frac{1}{4} ln (x - 1) - \frac{1}{4 ( x - 1 )} + c_{1}

Graph

Beliebte Beispiele

derivative of 2x^{1/4}(x^3-11)

\frac{d}{d x} (2 x^{\frac{1}{4}} (x^{3} - 11))

tangent f(x)=5x^2+4

t an g e n t f (x) = 5 x^{2} + 4

derivative of (-2/(2x+5))

\frac{d}{d x} (\frac{- 2}{2 x + 5})

(\partial)/(\partial y)((x+y)(x^2+2y^2))

\frac{\partial}{\partial y} ((x + y) (x^{2} + 2 y^{2}))

(dy)/(dt)+e^ty=-24e^t

\frac{d y}{d t} + e^{t} y = - 24 e^{t}