y^'=4y+y^4

Lösung

y^{^{'}} = 4 y + y^{4}

y = 3 \frac{4}{e ^{- 12 t - c_{1}} - 1}

Schritte zur Lösung

y^{'} (t) = 4 y + y^{4}

Solve Bernoulli ODE:

y = 3 \frac{4}{e ^{- 12 t - c_{1}} - 1}

y = 3 \frac{4}{e ^{- 12 t - c_{1}} - 1}

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