What is the integral of cos^3(x/(18)) ?

The integral of cos^3(x/(18)) is 18(sin(x/(18))-(sin^3(x/(18)))/3)+C

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integral of cos^3(x/(18))

\int cos^{3} (\frac{x}{18}) d x

18 (sin (\frac{x}{18}) - \frac{sin ^{3} ( \frac{x}{18} )}{3}) + C

Solution steps

\int cos^{3} (\frac{x}{18}) d x

Apply u-substitution

: \int cos^{3} (u) \cdot 18 d u

= \int cos^{3} (u) \cdot 18 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 18 \cdot \int cos^{3} (u) d u

Rewrite using trig identities

= 18 \cdot \int (1 - sin^{2} (u)) cos (u) d u

Apply u-substitution

: \int 1 - v^{2} d v

= 18 \cdot \int 1 - v^{2} d v

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 18 (\int 1 d v - \int v^{2} d v)

\int 1 d v = v

\int v^{2} d v = \frac{v ^{3}}{3}

= 18 (v - \frac{v ^{3}}{3})

Substitute back

= 18 (sin (\frac{x}{18}) - \frac{sin ^{3} ( \frac{x}{18} )}{3})

Add a constant to the solution

= 18 (sin (\frac{x}{18}) - \frac{sin ^{3} ( \frac{x}{18} )}{3}) + C

\int (5 x + 1) d x

y = \frac{5 x}{x + 2}, (3, 3)

\frac{\partial}{\partial x} (1 (x - y) e^{y + 2 x^{2}})

y + y^{^{''}} = 0

x \to 0 + lim (\frac{x}{x + ∣ x ∣})

What is the integral of cos^3(x/(18)) ?
The integral of cos^3(x/(18)) is 18(sin(x/(18))-(sin^3(x/(18)))/3)+C