What is the tangent of y=(5x)/(x+2),(3,3) ?

The tangent of y=(5x)/(x+2),(3,3) is y= 2/5 x+9/5

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tangent of y=(5x)/(x+2),(3,3)

tangent of

y = \frac{5 x}{x + 2}, (3, 3)

y = \frac{2}{5} x + \frac{9}{5}

Solution steps

Find the slope of

y = \frac{5 x}{x + 2} : \frac{d y}{d x} = \frac{10}{( x + 2 ) ^{2}}

Compute the slope of

y = \frac{5 x}{x + 2}

(3, 3) : m = \frac{2}{5}

Find the line with slope m=

\frac{2}{5}

and passing through

(3, 3) : y = \frac{2}{5} x + \frac{9}{5}

y = \frac{2}{5} x + \frac{9}{5}

\frac{\partial}{\partial x} (1 (x - y) e^{y + 2 x^{2}})

y + y^{^{''}} = 0

x \to 0 + lim (\frac{x}{x + ∣ x ∣})

\frac{\partial}{\partial x} (z^{3} - 3 x yz)

\frac{\partial}{\partial x} (e^{9 x e^{y}})

What is the tangent of y=(5x)/(x+2),(3,3) ?
The tangent of y=(5x)/(x+2),(3,3) is y= 2/5 x+9/5