3y^{''}-24y^'+36y=6sin(2x)

Lösung

3 y^{^{''}} - 24 y^{^{'}} + 36 y = 6 sin (2 x)

y = c_{1} e^{6 x} + c_{2} e^{2 x} + \frac{1}{20} sin (2 x) + \frac{1}{10} cos (2 x)

Schritte zur Lösung

3 y^{''} (x) - 24 y^{'} (x) + 36 y = 6 sin (2 x)

Solve linear ODE:

y = c_{1} e^{6 x} + c_{2} e^{2 x} + \frac{1}{20} sin (2 x) + \frac{1}{10} cos (2 x)

y = c_{1} e^{6 x} + c_{2} e^{2 x} + \frac{1}{20} sin (2 x) + \frac{1}{10} cos (2 x)

\int_{1}^{3} \frac{2}{4 + ( x - 1 ) ^{2}} d x

y^{^{'}} = \frac{2 y}{x}

x \to 0 lim (\frac{x ^{2}}{x})

\frac{d}{d x} (2 sec (cos (x)) + 2 tan (2 x))

x \to 5 lim (\frac{x ^{2} + k x - 20}{x - 5})