derivative of 2sec(cos(x)+2tan(2x))

Lösung

\frac{d}{d x} (2 sec (cos (x)) + 2 tan (2 x))

- 2 sec (cos (x)) tan (cos (x)) sin (x) + 4 sec^{2} (2 x)

Schritte zur Lösung

\frac{d}{d x} (2 sec (cos (x)) + 2 tan (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 sec (cos (x))) + \frac{d}{d x} (2 tan (2 x))

\frac{d}{d x} (2 sec (cos (x))) = - 2 sec (cos (x)) tan (cos (x)) sin (x)

\frac{d}{d x} (2 tan (2 x)) = 4 sec^{2} (2 x)

= - 2 sec (cos (x)) tan (cos (x)) sin (x) + 4 sec^{2} (2 x)

x \to 5 lim (\frac{x ^{2} + k x - 20}{x - 5})

s l o p e in t erce pt (1, 128), (4, 161)

\frac{d}{d x} (ln (- \frac{1}{x}))

y^{^{'}} = 0.0875 - \frac{7 y}{2000}, y (0) = 50

t an g e n t f (x) = \frac{( 3 x + 5 )}{1 + x}, at x = 1