y^'=2y+1

Lösung

y^{^{'}} = 2 y + 1

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{1}{2}

Schritte zur Lösung

y^{'} (t) = 2 y + 1

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{1}{2}

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{1}{2}

l a pl a ce t r an s f or m cos (t - \frac{2 π}{3})

\int \frac{x - 3}{8 x - x ^{2}} d x

d er i v a t i v e y = \frac{x + \frac{1}{x}}{2 x + \frac{1}{x}}

d er i v a t i v e f (x) = arctan (\frac{x - 1}{x + 1})

\frac{\partial}{\partial x} (ln (x^{2} y^{2}))