derivative f(x)=3x^2+32x+64

Lösung

ableitung von

f (x) = 3 x^{2} + 32 x + 64

6 x + 32

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} + 32 x + 64)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (32 x) + \frac{d}{d x} (64)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (32 x) = 32

\frac{d}{d x} (64) = 0

= 6 x + 32 + 0

Vereinfache

= 6 x + 32

a re a 3 x^{3}, [0, 6]

d er i v a t i v e g (x) = \frac{5}{x ^{3}}

\frac{d}{d x} ((2 x + 1)^{5} (3 x - 2)^{7})

\frac{d}{d x} (e^{- 3 x} sin (π x - \frac{π}{8}))

\int \frac{x + 3}{x ^{2} - 4} d x