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Beliebt Rechnen >

y^{''}+y=3e^{-6x},y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + y = 3 e^{- 6 x}, y (0) = 0, y^{^{'}} (0) = 0

Lösung

y = - \frac{3}{37} cos (x) + \frac{18}{37} sin (x) + \frac{3}{37} e^{- 6 x}

Schritte zur Lösung

y^{''} (x) + y = 3 e^{- 6 x}

Solve linear ODE:

y = - \frac{3}{37} cos (x) + \frac{18}{37} sin (x) + \frac{3}{37} e^{- 6 x}

y = - \frac{3}{37} cos (x) + \frac{18}{37} sin (x) + \frac{3}{37} e^{- 6 x}

Graph

Beliebte Beispiele

(D^2-2D+1)y=e^{2x}(e^x+1)^{-2}

(D^{2} - 2 D + 1) y = e^{2 x} (e^{x} + 1)^{- 2}

y^{''}-10y^'+25y=132x^2(e^{(5x)})

y^{^{''}} - 10 y^{^{'}} + 25 y = 132 x^{2} (e^{(5 x)})

y^{''}-2y=e^{2x}+x^2-1

y^{^{''}} - 2 y = e^{2 x} + x^{2} - 1

y^{''}-3y^'=2e^{2x}sin(x)

y^{^{''}} - 3 y^{^{'}} = 2 e^{2 x} sin (x)

y^{''}+y^'+y=e^{-t}+sin(2t)

y^{^{''}} + y^{^{'}} + y = e^{- t} + sin (2 t)