y=1-y^'x

Lösung

y = 1 - y^{^{'}} x

y = - \frac{c _{1}}{x} + 1

Schritte zur Lösung

y = 1 - y^{'} (x) x

Solve separable ODE:

y = - \frac{c _{1}}{x} + 1

y = - \frac{c _{1}}{x} + 1

\frac{d p}{d t} = (1 - p)

\frac{d y}{y} = sin (x) d x

y^{^{'}} = - sin (y)

y^{^{'}} = cy

\frac{d y}{d x} = \frac{sin ( x )}{4 y}, y (0) = - 8