y^'=cy

Lösung

y^{^{'}} = cy

y = e^{c t + c_{1}}

Schritte zur Lösung

y^{'} (t) = cy

Solve separable ODE:

y = e^{c t + c_{1}}

y = e^{c t + c_{1}}

\frac{d y}{d x} = \frac{sin ( x )}{4 y}, y (0) = - 8

\frac{d y}{d x} + y = 2, y (0) = 1

y^{^{'}} = y^{3} (x^{3} - x)

x \frac{d y}{d x} - y = 2 x^{3} y

\frac{d y}{d x} y = e^{x} x^{2} + 1