y^'=2y^{-2},y(0)=3

Lösung

y^{^{'}} = 2 y^{- 2}, y (0) = 3

y = 3 6 t + 27

Schritte zur Lösung

y^{'} (t) = 2 y^{- 2}

Solve separable ODE:

y = 3 6 t + 27

y = 3 6 t + 27

(y + 2) d x + 25 - x^{2} d y = 0

2 x^{2} y + 3 x y^{^{'}} - 15 y = 0

- 5 \frac{d y}{d x} = 2 y - 150

(ln (y))^{2} \frac{d y}{d x} = x^{2} y

y^{^{'}} + \frac{3}{x} y = \frac{1}{x}